Perl Guru Forums: Perl Programming Help: Beginner: Recursion and "local" variables.

CGI/Perl Guide | Learning Center | Forums | Advertise | Login

Site Search: in


	MAIN INDEX	SEARCH POSTS	WHO'S ONLINE	LOG IN

Home: Perl Programming Help: Beginner:
Recursion and "local" variables.

DrZed
User

Jul 3, 2000, 7:42 PM

Post #1 of 3 (389 views)

Recursion and "local" variables.	Can't Post

I've tried to use a local variable in a recursive routine, but I couldn't get it to work. I understand non-recursive uses for local, but I'm wondering if there's a better way to do what I want in a recursive routine.

What I want is a single variable (a hash) which can be accessed by the routine during multiple recursions.

What I'm using is something like the following:

&recuse($data);

sub recurse
{
my (%main_hash);
my ($data,$hash_ref) = (shift,shift | | \%main_hash);
....
&recurse($data,$hash_ref);
....
}

All manipulation of the 'main hash' is done through $hash_ref. So, the first call of the routine will assign $hash_ref to it's %main_hash and the reference will be passed to each recursion.

It works, but it seems a bit sloppy, since each recursion will be allocating space for a %main_hash that won't be used.

I'm just curious if there's a better way of doing this.

Dr. Zed

Kanji
User / Moderator

Jul 3, 2000, 8:18 PM

Post #2 of 3 (389 views)

Re: Recursion and "local" variables. [In reply to]	Can't Post

Define your hash and the sub definition in the same block so they share the same scope.

<BLOCKQUOTE><font size="1" face="Arial,Helvetica,sans serif">code:</font><HR>

#!/usr/bin/perl -w

my $data = 0;
recurse( $data );

{
my %hash;

sub recurse {
my $data = shift;
$data++;

print "%hash contains ",
( %hash ? join( ", " => keys %hash ) : "nothing" ),
"\n";

$hash{ $data } = 1;

recurse( $data ) unless keys %hash == 10;
}
}
__END__
%hash contains nothing
%hash contains 1
%hash contains 1, 2
%hash contains 1, 2, 3
%hash contains 1, 2, 3, 4
%hash contains 1, 2, 3, 4, 5
%hash contains 1, 2, 3, 4, 5, 6
%hash contains 7, 1, 2, 3, 4, 5, 6
%hash contains 1, 2, 3, 4, 5, 6, 7, 8
%hash contains 1, 2, 3, 4, 5, 6, 7, 8, 9</pre><HR></BLOCKQUOTE>
There is a proper name for this, but I forget offhand. (Closure?)

DrZed
User

Jul 3, 2000, 11:50 PM

Post #3 of 3 (389 views)

Re: Recursion and "local" variables. [In reply to]	Can't Post

Well, that's closer to what I wanted, and I can make that work.

The only quirk is that the data will keep it's data between calls. I need something that's new to each call the first time it's called.

Hmmm.... If you make the outer parenthesis a subroutine and make the hash a local variable...

Code

#!/usr/bin/perl -w 
 
parse(0); 
print "="x40,"\n"; 
parse(0); 
 
sub parse 
{local %hash; 
 &recurse; 
 sub recurse 
 {my $data = shift; 
  $data++; 
  print "%hash contains ", 
   ( %hash ? join( ", " => keys %hash ) : "nothing" ),"\n"; 
  $hash{ $data } = 1; 
  recurse( $data ) unless keys %hash == 10; 
 } 
} 
[\code] 
 
That's basically what I was looking for. 
 
Thanks. 
 
Dr. Zed

Search for (options)

Web Applications & Managed Hosting Powered by Gossamer Threads
Visit our Mailing List Archives