
roniz5
New User
Feb 18, 2007, 12:25 AM
Post #1 of 2
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$1 not containing real string from brackets
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Hi I'm trying to sort a file according to a hexa value that appears in every line. Since I don't remember how to convert hex2int, I tryed and noticed that this works: $val1= "0x0A"; $val2=10; if ($val1 == $val2) {print "OK";} So, I tryed to use just a simple compare as the above in my script that sorts the file. But here I encountered this problem: $1 does not get the whole meaning of the string in brackets. What do I mean? look at the next lines, they should have worked but they don't: $val1=10; $val2="this line contains the value 0x0A"; if ($val2 =~ /the value (0x\w)/) {if ($val1 == $1) {print "OK";}} This did not work!! Just to show that the problem is with the $1 interpretation, I printed out to the screen the content of $1 and it printed out correctly: 0x0A. Can someone explain this to me? Thanks Roni roniz5@yahoo.com
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