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Adding variable to existing variable

devonbosch
New User

Mar 8, 2007, 4:00 AM

Post #1 of 4 (349 views)

Adding variable to existing variable	Can't Post

I have sendind data from a form to this sub. The data consist of many rooms, which is selected by a drop-down box. I've tried $fields{'rtqty$count'} asswell, but nothing seems to work. Please help... $count = 1; if ($fields{'rtqty'} .$count ne "")
{
while ($count <= $fields{'rtqty'} . $count)
{
$rooms = $rooms . "Room: $fields{'name'} . $count<br>";
$count ++;
} }

KevinR
Veteran

Mar 8, 2007, 9:04 AM

Post #2 of 4 (347 views)

Re: [devonbosch] Adding variable to existing variable [In reply to]	Can't Post

I don't understand your question.
-------------------------------------------------

rheydenr
Novice

Mar 14, 2007, 2:56 AM

Post #3 of 4 (340 views)

Re: [devonbosch] Adding variable to existing variable [In reply to]	Can't Post

Hi devonbosch,
you can try $fields{"rtqty$count"} (with double quotes!). This should work.
A construct like $fields{'rtqty'} . $count won't work as expected, since it concatenates the values as string. Perhaps it works with eval, but the upper proposal should be better.

HTH,
Ralf.

devonbosch
New User

Mar 14, 2007, 5:03 AM

Post #4 of 4 (336 views)

Re: [rheydenr] Adding variable to existing variable [In reply to]	Can't Post

Thanks for your reply. I found the solution throught trial and error. This is what I have done:

Code

 while 
{  
$rtidt = rtqty . "$nr";  
 
$rtid2 = $fields{$rtidt};$nr ++; 
 
 
 
 
}

(This post was edited by devonbosch on Mar 14, 2007, 5:06 AM)

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