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interpreting subarray in list context

amuses
New User

Apr 13, 2007, 8:39 AM

Post #1 of 2 (265 views)

interpreting subarray in list context	Can't Post

@a1 = ( 4 , 5, 6);
($x, $y, $z) = @a1[0..2];
print "$x, $y, $z\n"; #outputs 4 5 6 as expected

@a2 = ();
$a2[0] = [4, 5, 6]; # a sub-array
($x, $y, $z) = $a2[0][0..2]; # DOESNT WORK THE SAME

So what's the correct analogous syntax to do this?

And by analogous I mean, not this:
($x, $y, $z) = ($a2[0][0] , $a2[0][1], $a2[0][2]);
which works, but is not analogous.

This mystery has been illuding me for years.

KevinR
Veteran

Apr 13, 2007, 10:27 AM

Post #2 of 2 (263 views)

Re: [amuses] interpreting subarray in list context [In reply to]	Can't Post

Code

@a2 = (); 
$a2[0] = [4, 5, 6];  
($x, $y, $z) = @{$a2[0]}; 
print "$x, $y, $z";

Code

@a2 = (); 
$a2[0] = [3, 4, 5, 6, 7, 8];  
($x, $y, $z) = @{$a2[0]}[1..3];  
print "$x, $y, $z";

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