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& operator in perl

klusener
Novice

Jan 29, 2008, 6:55 AM

Post #1 of 3 (253 views)

& operator in perl	Can't Post

Hello All,

What does the following line of code mean

if ( &look_up( $var1 ) )

What i dont understand is the use of "&" keyword in the begining of the if test.

Thanks in advance.

KevinR
Veteran

Jan 29, 2008, 12:33 PM

Post #2 of 3 (251 views)

Re: [klusener] & operator in perl [In reply to]	Can't Post

& in that context means "look_up" is a sub routine:

To call subroutines:

NAME(LIST); # & is optional with parentheses.
NAME LIST; # Parentheses optional if predeclared/imported.
&NAME(LIST); # Circumvent prototypes.
&NAME; # Makes current @_ visible to called subroutine.

Read this page for more details about how & affects your perl scripts behavior: http://perldoc.perl.org/perlsub.html
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(This post was edited by KevinR on Jan 29, 2008, 12:34 PM)

klusener
Novice

Jan 29, 2008, 2:00 PM

Post #3 of 3 (249 views)

Re: [KevinR] & operator in perl [In reply to]	Can't Post

Thanks i got the point :).

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