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($a=($b=2)=3 ) returns 1 !?

ip
New User

Apr 15, 2008, 1:58 PM

Post #1 of 2 (402 views)

($a=($b=2)=3 ) returns 1 !?	Can't Post

So, I was sure that the result should be 3, but it's not. Can someone explain why $a is 1 after evaluating

Code

$a=($b=2)=3;

KevinR
Veteran

Apr 15, 2008, 11:51 PM

Post #2 of 2 (396 views)

Re: [ip] ($a=($b=2)=3 ) returns 1 !? [In reply to]	Can't Post

looks like $a is a list in scalar context, which means it returns the number of items in the list. Just a guess though.
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