Perl Guru Forums: Perl Programming Help: Regular Expressions: capturing parentheses in subseraches

CGI/Perl Guide | Learning Center | Forums | Advertise | Login

Site Search: in


	MAIN INDEX	SEARCH POSTS	WHO'S ONLINE	LOG IN

Home: Perl Programming Help: Regular Expressions:
capturing parentheses in subseraches

PGScooter
stranger

Jun 12, 2008, 1:21 AM

Post #1 of 3 (2116 views)

capturing parentheses in subseraches	Can't Post

Hi, I know I've read this a couple of times, but forgot how it is correctly done. Suppose I do a regex search, condition on it and within that if block, I do another regex search. How do I refer to the capturing parentheses in the subsearch? Because don't $1,$2,... refer to the main search, not the nested one?

if ($string=~/(\w*)end/) {

if ($diffstring=~/$1five(\w*\d{2})/) {

print "don't know"; #how do I get what's in (\w*\d{2})?

}

}

thanks
The more you teach me, the more I learn. The more I learn, the more I teach.

KevinR
Veteran

Jun 12, 2008, 8:35 AM

Post #2 of 3 (2103 views)

Re: [PGScooter] capturing parentheses in subseraches [In reply to]	Can't Post

Code

   
 
if ($string=~/(\w*)end/) { 
 
   $foo = $1;   
 
   if ($diffstring=~/${foo}five(\w*\d{2})/) {  
 
      print $1; 
 
}  
 
}

-------------------------------------------------

PGScooter
stranger

Jun 12, 2008, 1:30 PM

Post #3 of 3 (2088 views)

Re: [KevinR] capturing parentheses in subseraches [In reply to]	Can't Post

ah, that definitely makes sense! For some reason I thought I had seen a special way to refer to a nested one, but your way seems perfect.

Thanks!
The more you teach me, the more I learn. The more I learn, the more I teach.

Search for (options)

Web Applications & Managed Hosting Powered by Gossamer Threads
Visit our Mailing List Archives