CGI/Perl Guide | Learning Center | Forums | Advertise | Login Site Search: in Perl Guide PerlGuru Forums Learning Ctr

	MAIN INDEX	SEARCH POSTS	WHO'S ONLINE	LOG IN

Home: Perl Programming Help: Intermediate: file creation

1951g New User Jun 16, 2008, 3:27 PM Post #1 of 6 (2395 views) file creation Can't Post I want to write a perlscript that will traverse through a series of subdirectories and print out a dynamic string to a new file that will be executed separately from perlscript that created it. The perlscript would take 2 arguments: directory name and destination server. So if I passed the following 2 arguments to the perlscript: /opt/oracle/oradata destServerXYZ It would generate the following in a file that I would execute later. cp /opt/oracle/oradata01/redo1.dbf cp /opt/oracle/oradata01/control1.dbf cp /opt/oracle/oradata02/redo1.dbf cp /opt/oracle/oradata03/subdir/usertablespace.dbf Is there a good way to do this with a perlscript so no matter what server I'm on or directory structure I give, it'll start at the top level of the directory I give and traverse through subdirectories and files to construct the cp statements? Thanks for any help with this.

KevinR Veteran Jun 16, 2008, 5:03 PM Post #2 of 6 (2389 views) Re: [1951g] file creation [In reply to] Can't Post If you want to traverse a directory and all of its subdirectories use the File::Find module. -------------------------------------------------

meloyelo User Jun 16, 2008, 10:40 PM Post #3 of 6 (2384 views) Re: [1951g] file creation [In reply to] Can't Post The cp commands you show are not complete - they only have one argument. How is destServerXYZ part of what you want to do? Also, you might be able to do this with just the Unix find utility: find /opt/oracle/oradata -name '*.dbf' -exec echo cp '{}' ... ';'

1951g New User Jun 17, 2008, 6:47 AM Post #4 of 6 (2376 views) Re: [meloyelo] file creation [In reply to] Can't Post Yes, I accidentially left off the last part. Actually, I'm going to be using rsync instead of cp since I'm going from 1 server to another keeping same directory structure but wanted to be able to use this perlscript as a utility to run on any server giving it the 2 arguments to construct the directories. rsync /opt/oracle/oradata01/redo1.dbf destinationserver:/opt/oracle/oradata01/redo1.dbf rsync /opt/oracle/oradata01/control1.dbf destinationserver:/opt/oracle/oradata01/control1.dbf rsync /opt/oracle/oradata02/redo1.dbf destinationserver:/opt/oracle/oradata02/redo1.dbf rsync /opt/oracle/oradata03/subdir/usertablespace.dbf destinationserver:/opt/oracle/oradata03/subdir/usertablespace.dbf Thanks.

1951g New User Jun 17, 2008, 6:48 AM Post #5 of 6 (2375 views) Re: [KevinR] file creation [In reply to] Can't Post Kevin, Thanks for the help. That's enough to get me going in the right direction.

meloyelo User Jun 17, 2008, 8:04 AM Post #6 of 6 (2371 views) Re: [1951g] file creation [In reply to] Can't Post You may not have to write any perl at all -- rsync has the capability to perform recursive copies and also to match file names (see the --include and --exclude options.)

Announcements     PerlGuru Announcements Perl Programming Help     Frequently Asked Questions     Beginner     Intermediate     Advanced     Regular Expressions     mod_perl     DBI     Win32 Programming Help Fun With Perl     Perl Quizzes - Learn Perl the Fun Way     Perl Golf     Perl Poetry Need a Custom or Prewritten Perl Program?     I need a program that...     I Need a Programmer for Freelance Work     Throw Down The Gauntlet General Discussions     General Questions     Feedback     Tutorial/Article Suggestions for The Learning Cent     Internet Security Other Programming Languages     Javascript     PHP

Search this forum this category all forums for All words Any words Whole Phrase (options)

Powered by Gossamer Forum v.1.2.0

Web Applications & Managed Hosting Powered by Gossamer Threads
Visit our Mailing List Archives