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How to return which part of the Regular Expression was triggered

Labrex
New User

Dec 1, 2008, 3:37 PM

Post #1 of 5 (1429 views)

How to return which part of the Regular Expression was triggered	Can't Post

Hi, it's a little difficult for me to explain this, but is there any way to return the part of the regex that was used to match the pattern.

For example:

my $key = 'cd';

if ($key =~ /AB|CD|EF|GH/i)
{
# I want to print out the part of the regex that was used to
# to match the pattern. In this case it would be 'CD'.
}

Thank. I really appreciate your time.

KevinR
Veteran

Dec 1, 2008, 4:26 PM

Post #2 of 5 (1419 views)

Re: [Labrex] How to return which part of the Regular Expression was triggered [In reply to]	Can't Post

There might be other ways, but you can use a capturing group () and display the match that way:

Code

my $key = 'cd';  
 
if ($key =~ /(AB|CD|EF|GH)/i) { 
   print "$1\n";  
}

-------------------------------------------------

Labrex
New User

Dec 1, 2008, 4:34 PM

Post #3 of 5 (1416 views)

Re: [KevinR] How to return which part of the Regular Expression was triggered [In reply to]	Can't Post

Thanks for your help Kevin, but when I tried that, it prints out 'cd' instead of 'CD'. But that may be okay since it's case insensitive. Thanks.

(This post was edited by Labrex on Dec 1, 2008, 4:35 PM)

KevinR
Veteran

Dec 1, 2008, 5:04 PM

Post #4 of 5 (1410 views)

Re: [Labrex] How to return which part of the Regular Expression was triggered [In reply to]	Can't Post

Code

my $key = 'cd';   
  
if ($key =~ /(AB|CD|EF|GH)/i) {  
   print uc($1),"\n";   
}

-------------------------------------------------

Labrex
New User

Dec 1, 2008, 5:21 PM

Post #5 of 5 (1409 views)

Re: [KevinR] How to return which part of the Regular Expression was triggered [In reply to]	Can't Post

Thanks, you have been of great help. I really appreciate it.

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