jigneshjsoni
User
Feb 15, 2009, 2:23 PM
Post #1 of 1
(1304 views)
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"defined" in while loop
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1) while(<stdin>){print " I saw $_" ;}
# Is thie equivalent to
2) while($_=<stdin>){ print "I saw $_" ;}
If it is so, , how will this code end after printing "I saw whateverentered"
As there is no "defined" used in while loop , so how will while loop end because undefined value in the $_ will not let the loop end.
3) while(defined($_= <stdin>)){print "I saw $_ " ;}
In either of these three codes, output is the same.
While I was going thru book, it is stated for the first code "Read a line of input and see if its true. And if its true, enter the while loop but throw away that line of input." What does this mean ? Does it mean that line of input will be read but not printed ? Why not ? Because by default any input will be assigned to $_.
Pls explain.
(This post was edited by jigneshjsoni on Feb 15, 2009, 2:33 PM)
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