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absoulte path for symbolic link

rahulgupta70
New User

May 19, 2009, 9:52 PM

Post #1 of 4 (5661 views)

absoulte path for symbolic link	Can't Post

In unix in creatd a symbolic link

/data/rdmst11/abc.v -> /home/user/pqr/file_name123

Now to my perl script (test.pl) in directory /data/rdmst11/abc/mydir/ I provided ../../abc.v as the input.

When i use cwd::abs_path("../../abc.v") it gives me /home/user/pqr/file_name123 as the return value. That means it has resolved the symbolic link.
I want a way by which I get /data/rdmst11/abc.v as the output in which the symbolic link has not been resolved

Regards

1arryb
User

May 20, 2009, 1:55 PM

Post #2 of 4 (5644 views)

Re: [rahulgupta70] absoulte path for symbolic link [In reply to]	Can't Post

Hi rahu,

Get the abs_path of the directory component to avoid traversing the link at the file level (of course, this won't work if '../../' is also a link):

Code

#!/usr/bin/perl 
# 
use strict; 
use warnings; 
 
use Cwd qw(abs_path); 
use File::Basename; 
 
my $link = $ARGV[0]; 
die "usage: $0 <link_name>" unless $link; 
unless (-l $link) { 
    print "WARNING: $link isn't a symlink. This won't prove anything.\n"; 
} 
print abs_path(dirname($link)) . '/' . basename($link) . "\n";

Cheers,

Larry

(This post was edited by 1arryb on May 20, 2009, 1:56 PM)

rahulgupta70
New User

May 20, 2009, 10:23 PM

Post #3 of 4 (5627 views)

Re: [1arryb] absoulte path for symbolic link [In reply to]	Can't Post

sub utilGetAbsoluteFileName{

my $fileName = shift;
$fileName =~ s/\/+/\//g;

if(! -e $fileName){
return $fileName;
}

my $dir = getcwd;
if ($fileName !~ /^\//){
$fileName = $dir."\/".$fileName;
}

my @targetArr = ();
my @fileArray = split "\/", $fileName;
for (my $index=0; $index<@fileArray; $index++){
next if($fileArray[$index] eq "\.");

if($fileArray[$index] eq "\.\."){
pop @targetArr;
}else{
push @targetArr, $fileArray[$index];
}
}

my $absFileName = join "/", @targetArr;

$absFileName =~ s/\/+/\//g;
return $absFileName;
}

I have written this API which calculates the absolute path for any filename in unix. It takes care of "../../" and "./". Please tell if i have missed any case.
Thanks

Code

 In Reply To

Code

rahulgupta70
New User

May 20, 2009, 10:24 PM

Post #4 of 4 (5626 views)

Re: [1arryb] absoulte path for symbolic link [In reply to]	Can't Post

Thanks Larry !!!

Rahul

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