jm8254og
New User
Aug 4, 2009, 5:16 PM
Post #1 of 2
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Automatically determing harddrive information such as filesystem type?
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Hello,
I am trying to create a script that will automatically determine the source and destination drives for making images. I have some known variables such as file system type and one drive, the source, will have a boot flag. I thought that the "df" command would solve my problem and works great on a local system but when I run it from a live cd environment it will only report the cd's information, makes sense I guess. I put what I have below: I have tried to do the same thing with "fdisk -l" and split but all I can get is the last line of the output of the fdisk command. Any ideas on what to do to make such a thing work in a live cd environment? Maybe I am going about it too difficult? The goal here is that someone could boot to a live CD that runs the script and determines what the source, internal drive, and destination, external drive, is and pass that to "dd"
open (df, "df -t ext 3 |"); #I will eventually change this to ntfs
while (<df>)
{
($src)=split;
}
$src = substr ($src, 5,3);
print "The Source Drive is $src\n";
open (df, "df -t vfat |");
while (<df>)
{
($dst)=split;
}
$dst= substr ($dst, 5,4);
print "The Destination Drive is $dst\n";
#pass those to dd and make image
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