Perl Guru Forums: Perl Programming Help: Regular Expressions: Replacing all occurrences of something in a part of a string

CGI/Perl Guide | Learning Center | Forums | Advertise | Login

Site Search: in


	MAIN INDEX	SEARCH POSTS	WHO'S ONLINE	LOG IN

Home: Perl Programming Help: Regular Expressions:
Replacing all occurrences of something in a part of a string

evgen-i
New User

Apr 15, 2010, 1:29 AM

Post #1 of 2 (6529 views)

Replacing all occurrences of something in a part of a string	Can't Post

Hi,

I wonder if it is possible to write a regular expression that replaces all occurrences of something (e.g. whitespace), but not in the whole string, but a part of a string that is identified by some matched characters.

In my particular example, I would like to replace all spaces with underscores between an opening and a closing parenthesis (possibly with multiple occurrences of (...) in the line).

"bla bla (this is some stuff in parens) bla (and again) bla" -> "bla bla (this_is_some_stuff_in_parens) bla (and_again) bla"

Thanks much!

roolic
User

Apr 15, 2010, 4:21 AM

Post #2 of 2 (6526 views)

Re: [evgen-i] Replacing all occurrences of something in a part of a string [In reply to]	Can't Post

Code

my $str = 'bla bla (this is some stuff in parens) bla (and again) bla'; 
 
while( $str =~ /\(([^\)]*?\s+[^\)]*?)\)/ ){ 
        my $substr = $newsubstr = $1; 
        $newsubstr =~ s/\s+/_/g; 
        # uncomment to see the progress 
        # print "old:'$substr'\nnew: '$newsubstr'\n"; 
        $str =~ s/\($substr\)/\($newsubstr\)/g; 
} 
 
print $str;

Search for (options)

Web Applications & Managed Hosting Powered by Gossamer Threads
Visit our Mailing List Archives