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about defined

makals
Novice

Jan 3, 2011, 6:23 AM

Post #1 of 5 (492 views)

about defined	Can't Post

hello

see this everyone:

my $input = shift;

if (defined $input and $input eq "-n") {

$numeric = 1;

$input = shift;

}

what does (defined) mean , and can you explain the first and the socend shift imean we shift from the ARGV and what happend if we shift again to the same variable?

shawnhcorey
Enthusiast

Jan 3, 2011, 7:23 AM

Post #2 of 5 (489 views)

Re: [makals] about defined [In reply to]	Can't Post

In Reply To

hello

see this everyone:

my $input = shift;

if (defined $input and $input eq "-n") {

$numeric = 1;

$input = shift;

}

what does (defined) mean , and can you explain the first and the socend shift imean we shift from the ARGV and what happend if we shift again to the same variable?

defined() returns false if the variable is undef. See `perldoc -f defined`.

If you're outside a subroutine, shift() will remove the first item in @ARGV. The second shift will store the next item in the variable. See `perldoc -f shift`.

__END__

I love Perl; it's the only language where you can bless your thingy.

Perl documentation is available at perldoc.perl.org. The list of standard modules and pragmatics is available in perlmodlib.

Get Markup Help. Please note the markup tag of "code".

makals
Novice

Jan 3, 2011, 9:56 AM

Post #3 of 5 (484 views)

Re: [shawnhcorey] about defined [In reply to]	Can't Post

thank you so do the variable store them both i mean the two shifts?

shawnhcorey
Enthusiast

Jan 3, 2011, 10:00 AM

Post #4 of 5 (483 views)

Re: [makals] about defined [In reply to]	Can't Post

No, variables that start with a $ store only one value. See `perldoc perldata`.

__END__

I love Perl; it's the only language where you can bless your thingy.

Perl documentation is available at perldoc.perl.org. The list of standard modules and pragmatics is available in perlmodlib.

Get Markup Help. Please note the markup tag of "code".

Karazam
User

Jan 4, 2011, 1:42 AM

Post #5 of 5 (466 views)

Re: [makals] about defined [In reply to]	Can't Post

What the code does is this. Imagine you call the script like so:

Code

somescript.pl -n file.txt

The program now shifts the first argument (-n) into $input. It then goes on to check if $input is defined and is "-n". If that is the case it sets $numeric to 1, and shifts the second argument (file.txt) into $input, which will now have the value "file.txt". The difference between this call and the call

Code

somescript.pl file.txt

will be that $numeric is set to 1, which I guess is meant to change some behavior later on in the program. I hope this clarifies things.

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