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Regex to find a match and extract the first value of a line

kadu
New User

Apr 2, 2011, 6:25 AM

Post #1 of 4 (4144 views)

Regex to find a match and extract the first value of a line	Can't Post

Hi,

I need a regex that looks for a match in a line and if found extract the first value of the line:

The list will look like this:

Code

0x1a0005c :     0   464   18x 436 :: -1 : "Pidgin" "Pidgin" : "Buddy List" : "buddy_list" 
0x2400003 :  1389   302   51x 598 :: -1 : "gkrellm" "Gkrellm" : "gkrellm" : "-NONE-" 
0x1c00004 :     0     0 1440x 400 :: -1 : "stjerm" "Stjerm" : "stjerm" : "-NONE-" 
0x1a00902 :     0    47   18x 415 :: -1 : "Pidgin" "Pidgin" : "Gustavo Erler" : "conversation"

I need to grep for a name (ex. stjerm) and if found give me the window ID, which is the first value in the line. On this case 0x1c00004

I've been trying this with grep and split but cannot get the result I want, instead grep is returning 1 (ie. it found a match).

Code

my ($id) = split (":", grep{/$app/} @wl);

Where $app contains the string I'm looking for (stjerm) and @wl contains the list of windows.

I'm sure it's possible to remove the split command and use a regex on grep that will match the string and then return me all contents before the first :

Thanks
Kadu

FishMonger
Veteran / Moderator

Apr 2, 2011, 10:15 AM

Post #2 of 4 (4125 views)

Re: [kadu] Regex to find a match and extract the first value of a line [In reply to]	Can't Post

Since grep returns the entire string, you'd need to do this in 2 steps to capture the desired data.

Instead, it would be better to loop over the data and use a single regex.

Code

#!/usr/bin/perl 
 
use strict; 
use warnings; 
use 5.010; 
 
my $app = 'stjerm'; 
 
while( <DATA> ) { 
    say $1 if /^(\S+).+$app/; 
} 
 
__DATA__ 
0x1a0005c :     0   464   18x 436 :: -1 : "Pidgin" "Pidgin" : "Buddy List" : "buddy_list" 
0x2400003 :  1389   302   51x 598 :: -1 : "gkrellm" "Gkrellm" : "gkrellm" : "-NONE-" 
0x1c00004 :     0     0 1440x 400 :: -1 : "stjerm" "Stjerm" : "stjerm" : "-NONE-" 
0x1a00902 :     0    47   18x 415 :: -1 : "Pidgin" "Pidgin" : "Gustavo Erler" : "conversation"

BillKSmith
Veteran

Apr 2, 2011, 10:23 AM

Post #3 of 4 (4123 views)

Re: [kadu] Regex to find a match and extract the first value of a line [In reply to]	Can't Post

You need grep to run in list context.

Code

use strict; 
use warnings; 
my $app = 'stjerm'; 
my @wl = ( 
    '0x1a0005c :     0   464   18x 436 :: -1 : "Pidgin" "Pidgin" : "Buddy List" : "buddy_list"', 
    '0x2400003 :  1389   302   51x 598 :: -1 : "gkrellm" "Gkrellm" : "gkrellm" : "-NONE-"', 
    '0x1c00004 :     0     0 1440x 400 :: -1 : "stjerm" "Stjerm" : "stjerm" : "-NONE-"', 
    '0x1a00902 :     0    47   18x 415 :: -1 : "Pidgin" "Pidgin" : "Gustavo Erler" : "conversation"', 
); 
my ($id) = split (":", (grep{/$app/} @wl)[0]); 
print $id, "\n";

Good Luck,
Bill

kadu
New User

Apr 2, 2011, 11:03 AM

Post #4 of 4 (4120 views)

Re: [BillKSmith] Regex to find a match and extract the first value of a line [In reply to]	Can't Post

Bill,

That did the trick.

Code

Thunderbird:  0x480006d   
conversation:  0x1a00902   
Geany:  0x4600003   
Firefox:  0x4a0006d   
buddy_list:  0x1a0005c   
Gkrellm:  0x2400003

Thank you.
Kadu

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