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[HELP] convert Perl script to Bash shell script

Egypte
New User

Apr 21, 2011, 7:50 AM

Post #1 of 2 (334 views)

[HELP] convert Perl script to Bash shell script	Can't Post

Hi everybody;

Need help converting the following Perl script to Bash shell script :

Code

#!/usr/bin/perl -w 
$SIG{INT} = 'IGNORE'; 
$SIG{TSTP} = 'IGNORE'; 
$SIG{TERM} = 'IGNORE'; 
$SIG{QUIT} = 'IGNORE'; 
print " Challenge1 : ";chomp($a=<STDIN>); 
print " Challenge2 : ";chomp($b=<STDIN>); 
while ($a ne  "123456" || $b ne "456789"){ 
print " Challenge1 : ";chomp($a=<STDIN>); 
print " Challenge2 : ";chomp($b=<STDIN>); 
}

I understand it's a simple while loop checks the STDIN values "Challenge1, and Challenege2" compared to "123456 and 456789" if correct it exit the loop or else ask for Challenges again. I'm pretty sure it's a nooby question and I'd better to learn Shell scripting but I really need it as soon as possible.

Also I've another question; How to store the reference values(i.e; 123456 and 456789) of Challenge1 and Challenge2 in an encrypted form say MD5 and even more save those values in another text file rather than showing them in the same shell script (i.e; compare STDIN to reference values in /home/user/challenges.txt).

Thanks in advance ;

rovf
Veteran

Apr 21, 2011, 9:07 AM

Post #2 of 2 (330 views)

Re: [Egypte] [HELP] convert Perl script to Bash shell script [In reply to]	Can't Post

For catching interrupts, see the 'trap' command of bash.

For the argument in the while loop, see the

$((....))

which is convenient for doing arithmetic evaluation.

For reading from STDIN, see the read command.

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