japhy
Enthusiast
Feb 18, 2000, 5:47 AM
Post #5 of 6
(478 views)
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kencl, perlkid -- you're missing the regular expression delimiters (the /'s).
To find out if a string is ONLY letters, I'd suggest doing:
<BLOCKQUOTE><font size="1" face="Arial,Helvetica,sans serif">code:</font><HR>
if ($string !~ /[^A-Za-z]/) {
# $string does not have any non-letters
}
</pre><HR></BLOCKQUOTE>
I suggest that, INSTEAD OF
<BLOCKQUOTE><font size="1" face="Arial,Helvetica,sans serif">code:</font><HR>
if ($string =~ /^[A-Za-z]+$/) {
# $string has all letters
}
</pre><HR></BLOCKQUOTE>
for TWO reasons. First, the one I suggest is
an application of logic (if $string is all letters, then it CAN'T have non-letters). Second, is because the $ anchor in a regex can match directly before a newline (which is NOT a letter). You can get around that by saying:
<BLOCKQUOTE><font size="1" face="Arial,Helvetica,sans serif">code:</font><HR>
if ($string =~ /^[A-Za-z]+(?!\n)$/) {
# ...
}
</pre><HR></BLOCKQUOTE>
Anyway. To match a string as all numbers, I'd suggest:
<BLOCKQUOTE><font size="1" face="Arial,Helvetica,sans serif">code:</font><HR>
if ($string !~ /\D/) {
# \d is the [0-9] char class
# \D is non-digits
}
</pre><HR></BLOCKQUOTE>
Thus endeth the lesson.
[This message has been edited by japhy (edited 02-18-2000).]
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