kolyonl
New User
Sep 18, 2012, 12:33 PM
Post #1 of 3
(1005 views)
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Extremely Noobish Problem: IF
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Hi everyone.
I've actually started learning perl yesterday, haven't made much progress, but I read more than I write.
However, I have a very simple question.
I've searched google for operators for non-numerical values, such as "Yes".
This is my script:
say "Please enter first number";
my $number1 = <STDIN>;
chomp $number1;
say "Please enter second number";
my $number2 = <STDIN>;
chomp $number2;
my $add = $number1 + $number2;
say "Are you sure you want to add these two numbers together?";
my $yes = <STDIN>;
if ($yes == 1) {
print "The answer is $add \n";
}
else {
print "Okay then, I'll keep it to myself.";
}
If I replace
with
it says the argument isn't numeric in value. If I use only "=" it says it found a conditional that should be "==". Both changes in the script end up displaying the result whatever the answer is.
tl;dr, Instead of 1 and 0, how do I make it more user-friendly per se with Yes and No.
My guess is I need to predefine $yes, but how can I do so when $yes is defined by <STDIN> ?
(This post was edited by kolyonl on Sep 18, 2012, 12:34 PM)
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