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condtion check

ashish_chand
Novice

Mar 1, 2013, 4:13 AM

Post #1 of 8 (1104 views)

condtion check	Can't Post

I am new to the scripting and have few line of code to analyse:

if ( $f == 0 ) { $f=1; /"/ && do { $q=0; $_=substr($s,0,1,"") } };
if ( $q == 0 && /"/ ) { $_=substr($s,0,1,"");
if (/^$/) {$q=1} elsif (/,/) {$f=0;$q=1} };
if ( $q == 1 && /,/ ) { $f=0 };

in the above line i can see the condition is being checked for /"/ and /,/

can anyone please explain how its working and also explain the above line.

BillKSmith
Veteran

Mar 1, 2013, 6:27 AM

Post #2 of 8 (1098 views)

Re: [ashish_chand] condtion check [In reply to]	Can't Post

The following is a less idiomatic, but equivalent perl code.

Code

my $DOUBLE_QUOTE = q("); 
my $NULL_STRING  = q(); 
my $COMMA        = q(,); 
 
if ( $f == 0 ) { 
    $f = 1; 
    if ($_ =~ /$DOUBLE_QUOTE/) {    # $_ contains a DOUBLE QUOTE character? 
        $q = 0; 
        $_ = substr($s, 0, 1, $NULL_STRING);    # Remove first character of $s. 
    } 
} 
 
 
if ( $q == 0 ) { 
    if ( $_ =~ /$DOUBLE_QUOTE/ ) {  # $_ contains a DOUBLE QUOTE character? 
        $_ = substr( $s, 0, 1, $NULL_STRING);   # Remove first character of $s. 
    } 
} 
 
if ( $_ =~ /^$/ ) {                 # $_ is a NULL_STRING? 
    $q = 1; 
} 
elsif ( $_ =~ /$COMMA/ ) {          # $_ contains a COMMA? 
    $f = 0; 
    $q = 1; 
} 
 
if ( $q == 1 ) { 
    if ( $_ =~ /$COMMA/ ) { 
        $f = 0; 
    } 
}

Good Luck,
Bill

Kenosis
User

Mar 2, 2013, 12:36 PM

Post #3 of 8 (1083 views)

Re: [ashish_chand] condtion check [In reply to]	Can't Post

What a great question! There's some Perl short circuiting demonstrated here. For example:

Code

$f == 1 && $f = 0;

is functionally equivalent to:

Code

$f = 0 if $f == 1;

Why? Perl evaluates the first conjunct $f == 1 and, if true, proceeds to evaluate the second so the overall && statement can be evaluated. However, if the first conjunct is false, there's no need to evaluate the second, since the overall && statement is (already) false. This is the short circuit effect and why it's equivalent to $f = 0 if $f == 1. Obviously, this can impact code readability, as does using variables named only $f and $q.

We can see exactly how Perl views this short circuiting:

Code

perl -MO=Deparse,-P -e '$f == 1 and $f = 0' 
$f = 0 if $f == 1; 
-e syntax OK

Notice that it parsed the and statement (used here instead of &&) as a conditional statement.

Curiously, the code's author implicitly used Perl's default scalar, viz., $_, in the matching statement /"/, yet chose to use substr to remove its first character, instead of a substitution like s/.//.

(This post was edited by Kenosis on Mar 2, 2013, 12:38 PM)

Laurent_R
Veteran / Moderator

Mar 2, 2013, 2:34 PM

Post #4 of 8 (1076 views)

Re: [Kenosis] condtion check [In reply to]	Can't Post

In Reply To

Curiously, the code's author implicitly used Perl's default scalar, viz., $_, in the matching statement /"/, yet chose to use substr to remove its first character, instead of a substitution like s/.//.

Yes, I also found it a bit unusual to find the use of this plain vanilla use of the substr function in a piece of code that is otherwise highly Perl idiomatic and in which I would also have expected rather an s/// substitution.

But I guess I probably just do the same thing from time to time, mixing very perlish constructs with plain vanilla code.

Kenosis
User

Mar 2, 2013, 3:19 PM

Post #5 of 8 (1075 views)

Re: [Laurent_R] condtion check [In reply to]	Can't Post

Quote

But I guess I probably just do the same thing from time to time, mixing very perlish constructs with plain vanilla code.

Well, I've certainly never been guilty of doing that!!! Smile

Laurent_R
Veteran / Moderator

Mar 2, 2013, 3:55 PM

Post #6 of 8 (1073 views)

Re: [Kenosis] condtion check [In reply to]	Can't Post

Hmmm, I did not mean this to be a guilt.

Wink

Or, probably, you are making fun about me. Frown

Oh, well, go on, no problem, I probably did not explain my point properly.

(This post was edited by Laurent_R on Mar 2, 2013, 4:01 PM)

Kenosis
User

Mar 2, 2013, 4:07 PM

Post #7 of 8 (1070 views)

Re: [Laurent_R] condtion check [In reply to]	Can't Post

No, no, Laurent_R! I was only trying to say that I've done exactly the same thing! Sorry that my words weren't well chosen (or that my attempt at sarcasm failed)... Smile

(This post was edited by Kenosis on Mar 2, 2013, 4:27 PM)

ashish_chand
Novice

Mar 3, 2013, 10:48 PM

Post #8 of 8 (1053 views)

Re: [BillKSmith] condtion check [In reply to]	Can't Post

hi Smith ,

Thanks for providing me the soluion. it really make clear to get the logic used in the code.

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