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Need help in decoding the following PERL code


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Mar 11, 2013, 2:53 PM

Post #1 of 2 (422 views)
Need help in decoding the following PERL code Can't Post

can any one help decoding following....I have it in my source code

Mainly I would like to know ,what is there within this if condition if (! /\|$/

and is it like , while <not eof > read one line from file, remove newline from that end of the line and then print that line to testdata.emp.tmp ?

perl -e 'while (<>) { if (! /\|$/ ) { chomp; } print ;}' $testdata.emp> $testdata.emp.tmp



Mar 11, 2013, 3:21 PM

Post #2 of 2 (418 views)
Re: [showale] Need help in decoding the following PERL code [In reply to] Can't Post

This perl script's executed from the command line, reading each line of $testdata.emp and removes the end-of-record (a newline, in this case) from each line if the line doesn't end with "|". Output is directed to $testdata.emp.tmp

Here's the regex:

|||||+ - End match
||||+ - End of line
|||+ - Verticle bar's escaped (so it's not regarded as alternation)
||+ - Escape
|+ - Begin match
+ - Not the case

So, the condition evaluates to true and the line is chomped if the line doesn't end with "|".

In a script with __DATA__ :

use strict; 
use warnings;

while (<DATA>) {
if ( !/\|$/ ) {

Line 1
Line 2|
Line 3
Line 4|
Line 5
Line 6|


Line 1Line 2| 
Line 3Line 4|
Line 5Line 6|

Lines 1, 3 & 5 don't end with "|", so their ending newline was removed.

(This post was edited by Kenosis on Mar 11, 2013, 3:22 PM)


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