Perl Guru Forums: Perl Programming Help: Beginner: creating a hash within a subroutine call?

CGI/Perl Guide | Learning Center | Forums | Advertise | Login

Site Search: in


	MAIN INDEX	SEARCH POSTS	WHO'S ONLINE	LOG IN

Home: Perl Programming Help: Beginner:
creating a hash within a subroutine call?

perlFun
Novice

Jun 19, 2013, 8:28 AM

Post #1 of 2 (333 views)

creating a hash within a subroutine call?	Can't Post

Hi, I've been trying to search for how to do this but wasn't finding any answer.

Suppose I have a subroutine that takes as one of its params a reference to a hash

sub _my_sub {
my $hashRef = shift;
.... (do stuff with my hash reference)
return 0; (just an example)
}

now say I want to call this subroutine but I don't actually want to have to initialize a hash before doing it.

What I mean is, I don't want to have to do this:

my %ages = ("John", 43, "Paul", 25, "Marie", 22);
my $result = _my_sub(\%ages);

I want to be able to essentially make that hash on the fly, within the subroutine call. Meaning something like

my $result = _my_sub(\("John", 43, "Paul", 25, "Marie", 22));

(note: I know that syntax above is not correct. that's why I asked teh question because I"m not certain what WOULD be the correct syntax, or if this is even allowed in perl and if so, is it recommended, I wasn't sure if something weird would happen while doing this)

thanks so much!

(This post was edited by perlFun on Jun 19, 2013, 8:29 AM)

FishMonger
Veteran / Moderator

Jun 19, 2013, 8:48 AM

Post #2 of 2 (319 views)

Re: [perlFun] creating a hash within a subroutine call? [In reply to]	Can't Post

Code

use Data::Dumper; 
 
my $result = _my_sub( {John => 43, Paul => 25, Marie => 22} ); 
print $result; 
 
sub _my_sub { 
    my $hashRef = shift; 
    print Dumper $hashRef; 
    return 0; 
}

(This post was edited by FishMonger on Jun 19, 2013, 8:48 AM)

Search for (options)

Web Applications & Managed Hosting Powered by Gossamer Threads
Visit our Mailing List Archives