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pattern matching

SKS
New User

Jul 10, 2013, 9:07 PM

Post #1 of 4 (445 views)

pattern matching	Can't Post

Hi there,

I am a new perl user. I am trying to get a text in between two dots of a line, but my program returns the entire line.

For example: I have a text which looks like
My sampledata 1,2 for perl .version 1_1.

I used the following match statement
$x =~ m/(\.)(.*)(\.)/;

my output for $x should be version 1_1 but I am getting the entire line as my match.

I would greatly appreciate any help.
Thanks.

Laurent_R
Veteran / Moderator

Jul 10, 2013, 11:18 PM

Post #2 of 4 (436 views)

Re: [SKS] pattern matching [In reply to]	Can't Post

Try something like this:

Code

my $match = $1 if $x =~ /\.(.+)\./;

(This post was edited by Laurent_R on Jul 10, 2013, 11:19 PM)

BillKSmith
Veteran

Jul 11, 2013, 5:10 AM

Post #3 of 4 (429 views)

Re: [SKS] pattern matching [In reply to]	Can't Post

Change your match operator to a substitute. Match the entire string and replace the match with the part that you want.

Code

#$x =~ m/(\.)(.*)(\.)/; 
$x =~ s/^.*\.(.*)\..*$)/$1/;  
/code] 
Good Luck, 
Bill

SKS
New User

Jul 15, 2013, 11:55 PM

Post #4 of 4 (408 views)

Re: [SKS] pattern matching [In reply to]	Can't Post

Hi everyone,

The code worked when I used
$x =~ m/(\.(.*)\.)/;

Thanks for the kind suggestions.

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