Perl Guru Forums: Perl Programming Help: Regular Expressions: using quotemeta?

CGI/Perl Guide | Learning Center | Forums | Advertise | Login

Site Search: in


	MAIN INDEX	SEARCH POSTS	WHO'S ONLINE	LOG IN

Home: Perl Programming Help: Regular Expressions:
using quotemeta?

Grizz
Deleted

Jan 16, 2001, 12:54 PM

Post #1 of 7 (7378 views)

using quotemeta?	Can't Post

I would like to add a little security to a database manager without using -T since there would be too many variables
to untaint. I would like to use the quotemeta or Q on an incoming variable ie $in{'something'} .
print quotemeta('$in{'something'}'); or
print if m/\Q$in{'something'}\E/;
neither one of these look right.
I would like to clean out the variable and use it in the script that follows.
Maybe a substitution would be better but the list of metas would be long.
I'd appreciate any ideas,,,,Thanks

japhy
Enthusiast / Moderator

Jan 16, 2001, 1:36 PM

Post #2 of 7 (7375 views)

Re: using quotemeta? [In reply to]	Can't Post

Either method is fine.

Code

$safe = quotemeta $some{var}; 
if ($string =~ /$safe/) { ... } 
  
if ($string =~ /\Q$some{var}\E/) { ... }

However, if you're just using them in regexes BY THEMSELVES, forget about that, and use eq or index() instead:

Code

if ($string eq $some{var}) { 
  # exact match 
} 
  
if (index($string, $some{var}) != -1) { 
  # $some{var} is IN $string somewhere 
}

Jeff "japhy" Pinyan -- accomplished hacker, teacher, lecturer, and author

sleuth
Enthusiast

Jan 16, 2001, 1:37 PM

Post #3 of 7 (7375 views)

Re: using quotemeta? [In reply to]	Can't Post

If you're using a hash to read all of the variables passed to you script you could do this.

foreach $key (%in){
$in{$key} =~ s!\W!!g;
}

That'll remove all NON Word characters. Just a short example, I'm sure you don't want to cut out numbers though, but you could modify it to remove the stuff you're looking to get rid of.

Sleuth

Grizz
Deleted

Jan 16, 2001, 4:42 PM

Post #4 of 7 (7373 views)

Re: using quotemeta? [In reply to]	Can't Post

Thanks for the input guys.
To jeff the hacker,
I'm already using if(exact match){--} to make decisions on what comes next. Are you saying this removes
metacharacters before they can be used against you?.........Thanks again

Grizz
Deleted

Jan 18, 2001, 9:05 AM

Post #5 of 7 (7363 views)

Re: using quotemeta? [In reply to]	Can't Post

I ended up trying
$in{'var'} =~ quotemeta $in{'var'};
this worked except it prints a backslash when the $var has a space..
trying to figure the proper way to use x to allow whitespace..maybe this ???
$in{'var'} =~ quotemeta $in{'var'}\x;

would also like to change this:
$in{'var1'} =~ quotemeta $in{'var1'};
$in{'var2'}=~ quotemeta $in{'var2'};
etc
etc.....to
$in{'all variables'} =~ quotemeta $in{'all variables'};

Time for another pot of coffee, Thanks....Chuck

japhy
Enthusiast / Moderator

Jan 18, 2001, 9:42 AM

Post #6 of 7 (7362 views)

Re: using quotemeta? [In reply to]	Can't Post

Grr, you're doing

Code

$foo =~ quotemeta($foo);

when you should be doing

Code

$foo = quotemeta($foo);

And if you want to quotemeta() a list of variables, like all the values in a hash, you can do this:

Code

$_ = quotemeta for @hash{keys %hash}; 
# or if you're using Perl 5.6.0 
$_ = quotemeta for values %hash;

Jeff "japhy" Pinyan -- accomplished hacker, teacher, lecturer, and author

cir
Novice

May 21, 2001, 7:19 AM

Post #7 of 7 (7302 views)

Re: using quotemeta? [In reply to]	Can't Post

"I'm already using if(exact match){--} to make decisions on what comes next. Are you saying this removes
metacharacters before they can be used against you?........."

What's special to regexes isn't special to the eq ne etc operators. So .+ would mean anything in a regex, whereas .+ would litterally mean .+ to those other operators.

http://

Search for (options)

Web Applications & Managed Hosting Powered by Gossamer Threads
Visit our Mailing List Archives