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using loop variable in regex subsitution

meir
New User

Jan 21, 2014, 12:38 AM

Post #1 of 2 (1987 views)

using loop variable in regex subsitution	Can't Post

Code

#!/usr/bin/perl -w 
use strict; 
 
my $find = "work"; 
my $replace ; 
my $string = "why doesnt this work?"; 
 
for($replace = 0; $replace < 3;  $replace++) { 
   print "string before regex = $string\n"; 
   $string  =~ s/$find/$replace/; 
   print "string after regex = $string\n"; 
}

I get result:
string before regex = why doesnt this work?
string after regex = why doesnt this 0?
string before regex = why doesnt this 0?
string after regex = why doesnt this 0?
string before regex = why doesnt this 0?
string after regex = why doesnt this 0

instead of the loop index being inserted into string
any ideas ? Thx

BillKSmith
Veteran

Jan 21, 2014, 5:21 AM

Post #2 of 2 (1971 views)

Re: [meir] using loop variable in regex subsitution [In reply to]	Can't Post

It does work! After the first substitution, there is no 'work' left to replace.

Perhaps this is what you mean

Code

use strict; 
my $find = "work"; 
my $replace; 
for ( my $replace = 0; $replace < 3; $replace++ ) { 
    my $string = "why doesnt this work?"; 
    print "string before regex = $string\n"; 
    $string =~ s/$find/$replace/; 
    print "string after regex = $string\n"; 
}

Output:

Code

string before regex = why doesnt this work? 
string after regex = why doesnt this 0? 
string before regex = why doesnt this work? 
string after regex = why doesnt this 1? 
string before regex = why doesnt this work? 
string after regex = why doesnt this 2?

Good Luck,
Bill

(This post was edited by BillKSmith on Jan 21, 2014, 5:43 AM)

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