Jasmine
Administrator
Jan 19, 2001, 3:32 PM
Post #1 of 1
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Why does passing a subroutine an undefined element
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(From the Perl FAQ)
Why does passing a subroutine an undefined element in a hash create it?
If you say something like: somefunc($hash{"nonesuch key here"});
This has been fixed as of perl5.004.
Normally, merely accessing a key's value for a nonexistent key does not cause that key to be forever there. This is different than awk's behavior.
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