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search and replace

cool_cake20
Novice

Jul 30, 2014, 3:44 AM

Post #1 of 6 (782 views)

search and replace	Can't Post

Hi ,

I am new to perl.

I need to search for the code line where it ends with ")" and ";"

Code

case1 : $display("i am new to perl ") ; 
case2 : $display("i am new to perl ")    ; 
case3 : $display("i am new to perl ")       ; 
 
replace them with 
 
case1 : $display("i am new to perl ")  
case2 : $display("i am new to perl ")  
case3 : $display("i am new to perl ")  
 
that means i need search for the combination of ")" and ";" ignoring the white space between them. 
 
how can i do that.

BillKSmith
Veteran

Jul 30, 2014, 4:51 AM

Post #2 of 6 (779 views)

Re: [cool_cake20] search and replace [In reply to]	Can't Post

This is a job for a regular expression. Read the perl documentation perlre, perlretut, perlrequick.

You can use a one-liner:

Code

perl -pe"s/)\s*;\s*$/);/" infile >outfile

Note: Replace double quotes with single quotes on almost any system but windows.
Good Luck,
Bill

cool_cake20
Novice

Jul 30, 2014, 7:50 AM

Post #3 of 6 (771 views)

Re: [BillKSmith] search and replace [In reply to]	Can't Post

Thanks BillKSmith, it worked.
Sure, i will go thorough the documents that you have mentioned.

Laurent_R
Veteran / Moderator

Jul 30, 2014, 9:22 AM

Post #4 of 6 (763 views)

Re: [BillKSmith] search and replace [In reply to]	Can't Post

Hi B ill,

the OP apparently wants to remove the semi-colon and keep the closing parens. So your Perl on e-liner should be modified as follows:

Code

perl -pe"s/)\s*;\/)/" infile >outfile

BillKSmith
Veteran

Jul 30, 2014, 9:35 AM

Post #5 of 6 (761 views)

Re: [Laurent_R] search and replace [In reply to]	Can't Post

Neither of seem to have noticed that the text and example in the original post disagree with each other. We each solved one of the problems.
Good Luck,
Bill

cool_cake20
Novice

Jul 30, 2014, 9:22 PM

Post #6 of 6 (744 views)

Re: [BillKSmith] search and replace [In reply to]	Can't Post

Hi Laurent_R

I initially tried the code that Bill mentioned ,but getting some errors.
I did little modification to it.
This is my working code.

Code

     $line =~ s/\)\s*;/\)/;

Thanks

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